(3x-2)(2x+1)=6x^2-x-5

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Solution for (3x-2)(2x+1)=6x^2-x-5 equation: 



(3x-2)(2x+1)=6x^2-x-5

We move all terms to the left:

(3x-2)(2x+1)-(6x^2-x-5)=0

We get rid of parentheses

-6x^2+(3x-2)(2x+1)+x+5=0

We multiply parentheses ..

-6x^2+(+6x^2+3x-4x-2)+x+5=0

We get rid of parentheses

-6x^2+6x^2+3x-4x+x-2+5=0

We add all the numbers together, and all the variables

3!=0

There is no solution for this equation

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